CRAC Class C (2025) — Questions 1151–1160

Unofficial study reference only. Not affiliated with the FCC, NCVEC or CRAC — official sources prevail. 非官方学习参考,与 FCC、NCVEC、CRAC 无隶属关系;以官方发布为准。

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U1320. When using an SDR transceiver, we often see window- function options related to the spectrum display in the system settings, such as Hamming, raised cosine, or Blackman. These are mainly used to: (Choose all that apply.)

使用SDR收发信机时,我们常在系统设置中看到与频谱显示有 关的窗函数选项,例如汉明、升余弦或布莱克曼等。这些主要 用来:

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A window function (窗函数), such as Hamming (汉明), raised cosine (升余弦), or Blackman (布莱克曼), is multiplied with the sampled data before performing the FFT (a fast algorithm for the discrete Fourier transform). Its primary purpose is to taper the data block and reduce spectral leakage (谱泄漏) caused by the discontinuity at the block edges, so the true shape of the signal's power spectrum is revealed (A). A good window also sharpens the measured peaks, improving the precision of amplitude and frequency estimates and thus the observation accuracy (B). C is wrong because windowing does not change the display-window width — that is a screen/span setting; D is wrong because windowing is a general spectral-analysis tool, not a technique specific to keyed modes like CW or RTTY. 测量与仪表 Measurement and Instruments

U0630. A multimeter's DC voltage range is used to measure a bipolar symmetric square-wave voltage (duty cycle 1:1). The reading obtained is:

用万用表的直流电压档测量正负对称的方波电压(占空比为 1:1)。所得读数为:

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A DC voltmeter reads the average (mean) value. A bipolar symmetric square wave that spends equal time at +V and −V has an average of zero, so the reading is zero (A).

U0631. If a moving-coil (magneto-electric) multimeter's AC voltage range is used to measure a bipolar symmetric square-wave voltage (duty cycle 1:1), the voltage reading shown by its pointer:

如果用磁电式万用表的交流电压档测量正负对称的方波电压 (占空比为1:1),其指针所示的电压读数:

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A moving-coil AC meter rectifies the waveform and is calibrated to read the RMS value of a sine wave (using the sine form factor ≈1.11). A square wave has a rectified average equal to its peak (Vpk); multiplying by 1.11 yields about 1.11·Vpk, which exceeds the peak (A). It is neither the peak (B), peak-to- peak (C), nor the average (D).

U0632. Using an analog (pointer) multimeter's DC voltage range to measure a square-wave voltage whose minimum value is 0 (duty cycle 1:1), the reading obtained is which value of the voltage:

用指针式万用表的直流电压档测量最小值为0的方波电压(占空 比为1:1),得到的读数是该电压的:

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A 0-to-Vpk square wave at 50% duty has an average = Vpk/2. A DC meter reads this average. For this waveform the RMS value also equals Vpk/2 (since RMS² = (Vpk²·0.5 + 0²·0.5) = Vpk²/2). So the reading is half the peak and equals the RMS value (A).

U0633. A multimeter's resistance range is used to measure a circuit. At first the meter indicates a very small resistance for the circuit, but as the measurement time lengthens the reading becomes increasingly large. This is because:

用万用表的电阻档测量一个电路。最开始,电表指示电路的阻 值很小。但是随着测量时间的延长,测量值却变得越来越大。 这是因为:

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An ohmmeter supplies a small current to measure resistance. If a large capacitor is across the circuit, it initially acts like a short (low reading) while charging, then its impedance rises as it fills, so the reading climbs toward infinity (A). A large inductor would instead show a rising-then-settling or initially high reading, not this pattern; an AC source or fault (C/D/B) does not explain the gradual rise.

U0634. To check whether an electrolytic capacitor is sound, one should use: (Choose all that apply.)

测量一个电解电容器是否完好应当使用:

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A sound electrolytic capacitor can be checked with an analog ohmmeter (it should show a charging swing to high resistance, A) and, more directly, with a digital multimeter's capacitance function if available (B). A current range (C) is unsuitable, and a charger plus short-circuit test (D) is dangerous and not a proper test.

U0635. Using an analog multimeter's resistance range to measure a common component, the first time the test leads are connected the pointer flicks and then quickly returns to zero; after disconnecting and reconnecting the leads, the pointer shows no indication at all. The correct inference is:

用指针式万用电表的电阻档测量一个常用元件,表笔第一次连 接时表针挥动了一下,但很快回到零点。断开表笔重新连接, 表针却不再有任何指示。正确的推论是:

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The behavior — an initial charging deflection on first connection, then settling, and little or no movement on a repeat connection (the component having retained charge) — is consistent with an electrolytic capacitor measured on an ohmmeter (A). The other options make absolute ("肯 定/definitely") claims that are not supported and are incorrect as the intended answer.

U0636. An analog multimeter's voltage range has an "ohms-per-volt" (ohms per volt) specification.

指针式万用表的电压档有个“欧姆/伏(每伏欧姆)”指标。越 大的每伏欧姆数越说明:

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Ohms-per-volt = the meter's input resistance per volt of range; a higher figure means higher input resistance, so the meter draws less current and disturbs the circuit less while measuring voltage (A). Lower ohms/volt means more loading (B wrong); it does not describe overload strength (C/D wrong).

U0637. Using a digital multimeter's DC voltage range to measure the voltage of a constant-amplitude audio signal between two points in a circuit, it is found that the reading is not zero. After swapping the two test leads and measuring again, the polarity of the reading reverses. The correct inference is:

用数字万用表的直流电压档测量电路两点间某个等幅音频信号 的电压,发现读数不为零。交换两支表笔之后再测,所得读数 的极性反转。正确的推论是:

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A pure AC/audio signal has zero average, so a DC voltmeter would read zero and swapping leads would not change a zero reading. A non-zero reading that flips polarity when the leads are swapped proves a DC offset (a DC component) is present on top of the audio (A). Harmonics, bandwidth, or lead capacitance would not produce this polarity-reversing DC reading.

U1321. Using an oscilloscope's AC-coupling mode, the measured voltage waveform of an equal-amplitude audio signal in the circuit is symmetric about zero (positive and negative). Now, after switching the input coupling to the DC position, the resulting waveform shows a significant vertical shift. The correct inference is:

用示波器的交流耦合档测得电路中某个等幅音频信号的电压波 形是正负对称的。现将输入耦合切换到直流档位,所得波形在 垂直方向上发生了显著偏移。正确的推论是:

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示波器的交流耦合 (AC coupling) inserts a series capacitor that blocks any DC component, so the displayed waveform is centered on zero — which is why the equal-amplitude (等幅) audio signal appeared symmetric about positive and negative. When the coupling is switched to 直流档 (DC coupling), the DC path is restored and the trace shifts vertically by an amount equal to the DC offset. A significant vertical shift therefore means a DC component is present in the signal itself (A). B is wrong because the oscilloscope does not add a bias — it merely stops removing the existing one; C (poor frequency response) and D (probe-to-ground stray capacitance) would not cause a simple steady vertical offset between AC and DC coupling.